How do you simplify ${(- \frac{1}{5})}^{- 2} + {(- 2)}^{- 2}$ $(- 1/5)^-2 + (-2)^-2$ ?

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Answer 1 · 2016-06-06T06:56:09

$\frac{1}{{(- \frac{1}{5})}^{2}} + \frac{1}{{(- 2)}^{2}} = 25 \frac{1}{4}$ $1/(-1/5)^2+1/(-2)^2=25 1/4$

As $a^{- n} = \frac{1}{a^{n}}$ $a^(-n)=1/a^n$ , ${(- \frac{1}{5})}^{- 2} + {(- 2)}^{- 2}$ $(-1/5)^(-2)+(-2)^(-2)$ can be written as

$\frac{1}{{(- \frac{1}{5})}^{2}} + \frac{1}{{(- 2)}^{2}}$ $1/(-1/5)^2+1/(-2)^2$

= $\frac{1}{\frac{{(- 1)}^{2}}{{(5)}^{2}}} + \frac{1}{4}$ $1/((-1)^2/(5)^2)+1/4$

= $\frac{1}{\frac{1}{25}} + \frac{1}{4}$ $1/(1/25)+1/4$

= $1 \times \frac{25}{1} + \frac{1}{4}$ $1xx25/1+1/4$

= $25 \frac{1}{4}$ $25 1/4$

How do you simplify (−15)−2+(−2)−2(- 1/5)^-2 + (-2)^-2?