Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you simplify #(1-2i)/(3-4i)#?

1 Answer

Mar 9, 2018

#(-2i+11)/25#

Explanation:

Multiply by the conjugate of #(3+4i)/(3+4i)# to cancel out the imaginary numbers in the denominator. Also remember that #i^2# is equal to -1.

#=(1-2i)/(3-4i) * (3+4i)/(3+4i)#
#=(3+4i-6i-8i^2)/(9+12i-12i-16i^2)#
#=(-2i+3-8(-1))/(9-16(-1))#
#=(-2i+11)/25#

Related questions

See all questions in Complex Number Plane

Impact of this question

2953 views around the world

You can reuse this answer
Creative Commons License