How do you simplify #(1-2i)-(3+4i)?# Precalculus Complex Numbers in Trigonometric Form Complex Number Plane 1 Answer Somebody N. Nov 3, 2017 #(-2-6i)# Explanation: For #(a +bi)# #(a_1 +b_1i)-(a_2 +b_2i)=(a_1-a_2 +b_1i-b_2i)# #:.# #(1-2i)-(3+4i)=(1-3+(-2i)-(4i))=(-2-6i)# Answer link Related questions What is the complex number plane? Which vectors define the complex number plane? What is the modulus of a complex number? How do I graph the complex number #3+4i# in the complex plane? How do I graph the complex number #2-3i# in the complex plane? How do I graph the complex number #-4+2i# in the complex plane? How do I graph the number 3 in the complex number plane? How do I graph the number #4i# in the complex number plane? How do I use graphing in the complex plane to add #2+4i# and #5+3i#? How do I use graphing in the complex plane to subtract #3+4i# from #-2+2i#? See all questions in Complex Number Plane Impact of this question 1450 views around the world You can reuse this answer Creative Commons License