How do you simplify $\frac{1 + 2 \sqrt{3}}{1 + \sqrt{3}}$ $(1+ 2 sqrt(3)) /( 1+ sqrt(3))$ ?

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How do you simplify $\frac{1 + 2 \sqrt{3}}{1 + \sqrt{3}}$ $(1+ 2 sqrt(3)) /( 1+ sqrt(3))$ ?

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Answer 1 · 2016-04-23T14:37:49

$= \frac{5 - \sqrt{3}}{2}$ $=(5-sqrt3)/2$

Explanation:

$= \frac{2 \sqrt{3} + 1}{\sqrt{3} + 1} = \frac{2 \sqrt{3} + 1}{\sqrt{3} + 1} \times \frac{\sqrt{3} - 1}{\sqrt{3} - 1}$ $=(2sqrt3+1)/(sqrt3+1)=(2sqrt3+1)/(sqrt3+1)xx(sqrt3-1)/(sqrt3-1)$
$= \frac{2 \sqrt{3} \cdot \sqrt{3} + \sqrt{3} - 2 \sqrt{3} - 1}{3 - 1}$ $=(2sqrt3*sqrt3+sqrt3-2sqrt3-1)/(3-1)$
$= \frac{5 - \sqrt{3}}{2}$ $=(5-sqrt3)/2$

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How do you simplify $\frac{1 + 2 \sqrt{3}}{1 + \sqrt{3}}$ $(1+ 2 sqrt(3)) /( 1+ sqrt(3))$ ?

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How do you simplify (1+ 2 sqrt(3)) /( 1+ sqrt(3))1+2√31+√3(1+ 2 sqrt(3)) /( 1+ sqrt(3))?

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How do you simplify $\frac{1 + 2 \sqrt{3}}{1 + \sqrt{3}}$ $(1+ 2 sqrt(3)) /( 1+ sqrt(3))$ ?