How do you simplify #(0.1x + 0.4y)^2#?

1 Answer
smendyka
Feb 14, 2017

See the entire solution process below:

Explanation:

We can rewrite this expression as:

#(0.1x + 0.4y)(0.1x + 0.4y)#

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(0.1x) + color(red)(0.4y))(color(blue)(0.1x) + color(blue)(0.4y))# becomes:

#(color(red)(0.1x) xx color(blue)(0.1x)) + (color(red)(0.1x) xx color(blue)(0.4y)) + (color(red)(0.4y) xx color(blue)(0.1x)) + (color(red)(0.4y) xx color(blue)(0.4y))#

#0.01x^2 + 0.04xy + 0.04xy + 0.16y^2#

We can now combine like terms:

#0.01x^2 + (0.04 + 0.04)xy + 0.16y^2#

#0.01x^2 + 0.08xy + 0.16y^2#

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