How do you show by substitution that the point (π /2, 1) lies on the curves of : $y=(2x)/pi$ ?

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Answer 1 · 2015-10-17T18:16:48

To show, that a point $(x,y)$ lies on a curve $y=f(x)$ you have to substitute $x$ and $y$ in the formula and check if left side equals right.

If you substitute you get:

$L=1$

$R=(2*(pi/2))/pi$
$R=pi/pi$

$R=1$

$L=R$

Left side equals right, so the point lies on the curve.

If you tried to calculate it for example for: $(0,1)$ you would get:

$L=y=1$

$R=(2x)/pi=(2*0)/pi=0/pi=0$

$0!=1$ , so the point $(0,1)$ does not lie on the curve.

How do you show by substitution that the point (π /2, 1) lies on the curves of : y=(2x)/piy=(2x)/pi?