How do you rewrite $Log_3 8 - 4log_3(x^2)$ as a single log?

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Answer 1 · 2015-10-30T11:37:46

$-8log_(3)8x$

By using laws of logs and exponents we get:

$log_(3)8-4log_3x^2=log_(3)8-8log_3x$

$=log_(3)8-log_3x^8$

$=log_3(8/x^8)$

$=log_(3)8x^(-8)$

$=-8log_(3)8x$

(Note: There might be other valid ways to express it as well)

How do you rewrite Log_3 8 - 4log_3(x^2)Log_3 8 - 4log_3(x^2) as a single log?