How do you remove discontinuity of #f(x) = (x^4 - 1)/(x-1)#?

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Answer 1 · 2015-04-12T21:35:52

You can write your numerator as #(x^2-1)(x^2+1)# where #(x^2-1)=(x-1)(x+1)# giving:
#f(x)=((x-1)(x+1)(x^2+1))/(x-1)=(x+1)(x^2+1)#