How do you rationalize the #sqrt5/sqrt8#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer GiĆ³ Mar 30, 2015 You can multiply and divide by #sqrt(8)# to get: #sqrt(5)/sqrt(8)*sqrt(8)/sqrt(8)=sqrt(5*8)/8=sqrt(40)/8=sqrt(4*10)/8=2sqrt(10)/8=sqrt(10)/4# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1524 views around the world You can reuse this answer Creative Commons License