How do you rationalize the denominator $(sqrt2)/(sqrt7+3)$ ?

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Answer 1 · 2015-06-04T17:53:06

Multiply the numerator and the denominator by $sqrt7 -3$ to have $(sqrt14 -3sqrt2)/(7-9)$

= $(sqrt14 -3sqrt2)/(-2)$

= $(3sqrt2-sqrt14)/2$

How do you rationalize the denominator (sqrt2)/(sqrt7+3)(sqrt2)/(sqrt7+3)?