How do you rationalize the denominator of square root of 18 over square root of 3?

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How do you rationalize the denominator of square root of 18 over square root of 3?

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Answer 1 · 2015-10-05T01:08:20

$\frac{\sqrt{18}}{\sqrt{3}} = \sqrt{6}$ $sqrt(18)/sqrt(3)=sqrt(6)$

Explanation:

$\frac{\sqrt{18}}{\sqrt{3}} = \frac{\sqrt{9} \sqrt{2}}{\sqrt{3}}$ $sqrt(18)/sqrt(3)=(sqrt(9)sqrt(2))/sqrt(3)$

Then we rationalise the denominator.

$\frac{\sqrt{9} \sqrt{2}}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} = \frac{3 \sqrt{2} \sqrt{3}}{3}$ $(sqrt(9)sqrt(2))/sqrt(3)xxsqrt(3)/sqrt(3)=(3sqrt(2)sqrt(3))/3$

Then we simplify

$\frac{3 \sqrt{2} \sqrt{3}}{3} = \sqrt{2} \sqrt{3} = \sqrt{6}$ $(3sqrt(2)sqrt(3))/3=sqrt(2)sqrt(3)=sqrt(6)$

Hope this helps :)

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How do you rationalize the denominator of square root of 18 over square root of 3?

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