How do you rationalize the denominator of 3 over quantity of 6 minus square root of 5? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Vishwaksen Reddy V. Oct 3, 2015 #(18+3*sqrt5)/31# Explanation: #3/(6-sqrt5)# #3/(6-sqrt5)##(6+sqrt5)/(6+sqrt5)# #3##((6+sqrt5)/(36-5))# #(18+3*sqrt5)/31# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1344 views around the world You can reuse this answer Creative Commons License