How do you rationalize the denominator and simplify #sqrt8/sqrt3#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Tony B May 14, 2016 #(2sqrt(6))/3# Explanation: Multiply by 1 but in the form of #1=sqrt(3)/(sqrt(3))# #sqrt(8)/sqrt(3)xxsqrt(3)/sqrt(3)# #(sqrt(8)xxsqrt(3))/3# #sqrt(8xx3)/3# #sqrt(2^2xx2xx3)/3# #(2sqrt(6))/3# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 938 views around the world You can reuse this answer Creative Commons License