How do you rationalize the denominator and simplify $\frac{\sqrt{4}}{\sqrt{6}}$ $sqrt4/sqrt6$ ?

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How do you rationalize the denominator and simplify $\frac{\sqrt{4}}{\sqrt{6}}$ $sqrt4/sqrt6$ ?

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Answer 1 · 2016-08-31T16:32:32

$\frac{\sqrt{6}}{3}$ $(sqrt6)/3$

Explanation:

We can start by first realizing that $\sqrt{4}$ $sqrt4$ is really just $2$ $2$ . So that makes it $\frac{2}{\sqrt{6}}$ $2/sqrt6$ .

We can take the next step by getting the square root out of the denominator.

$(\frac{2}{\sqrt{6}}) \cdot (\frac{\sqrt{6}}{\sqrt{6}})$ $(2/sqrt6)*(sqrt6/sqrt6)$ $=$ $=$ $\frac{2 \sqrt{6}}{{(\sqrt{6})}^{2}}$ $(2sqrt6)/(sqrt6)^2$ .

The squared and square root cancel each other out, leaving just $\frac{2 \sqrt{6}}{6}$ $(2sqrt6)/6$ .

Then you can simplify the $2$ $2$ in the numerator and $6$ $6$ in the denominator to just get $\frac{1 \sqrt{6}}{3}$ $(1sqrt6)/3$ , but you would not write the $1$ $1$ , so $\frac{\sqrt{6}}{3}$ $(sqrt6)/3$ .

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How do you rationalize the denominator and simplify $\frac{\sqrt{4}}{\sqrt{6}}$ $sqrt4/sqrt6$ ?

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How do you rationalize the denominator and simplify √4√6sqrt4/sqrt6?

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Explanation:

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How do you rationalize the denominator and simplify $\frac{\sqrt{4}}{\sqrt{6}}$ $sqrt4/sqrt6$ ?