How do you rationalize the denominator and simplify $\frac{\sqrt{36}}{\sqrt{8}}$ $sqrt36/sqrt8$ ?

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How do you rationalize the denominator and simplify $\frac{\sqrt{36}}{\sqrt{8}}$ $sqrt36/sqrt8$ ?

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Answer 1 · 2016-04-07T06:50:16

$\frac{\sqrt{36}}{\sqrt{8}} = \frac{3 \sqrt{2}}{2}$ $sqrt36/sqrt8=(3sqrt2)/2$

Explanation:

To rationalize the denominator in $\frac{\sqrt{36}}{\sqrt{8}}$ $sqrt36/sqrt8$ , let us examine the denominator.

As $\sqrt{8} = \sqrt{2 \times 2 \times 2} = 2 \sqrt{2}$ $sqrt8=sqrt(2xx2xx2)=2sqrt2$ , if we multiply this by $\sqrt{2}$ $sqrt2$ , it will become rational.

Hence multiplying numerator and denominator by $\sqrt{2}$ $sqrt2$ we get

$\frac{\sqrt{36}}{\sqrt{8}} = \frac{\sqrt{36} \times \sqrt{2}}{\sqrt{8} \times \sqrt{2}}$ $sqrt36/sqrt8=(sqrt36xxsqrt2)/(sqrt8xxsqrt2)$

= $(6sqrt2)/(sqrt16)=(6sqrt2)/4=(3cancel(6)sqrt2)/(2cancel4)=(3sqrt2)/2$

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How do you rationalize the denominator and simplify $\frac{\sqrt{36}}{\sqrt{8}}$ $sqrt36/sqrt8$ ?

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How do you rationalize the denominator and simplify sqrt36/sqrt8√36√8sqrt36/sqrt8?

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How do you rationalize the denominator and simplify $\frac{\sqrt{36}}{\sqrt{8}}$ $sqrt36/sqrt8$ ?