How do you rationalize the denominator and simplify $sqrt24/sqrt3$ ?

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Answer 1 · 2016-05-13T19:31:42

$sqrt(24)/sqrt(3) = 2sqrt(2)$

We will use:

The normal way to solve this example is to multiply both the numerator and denominator by $sqrt(3)$ first:

$sqrt(24)/sqrt(3) = (sqrt(24)*sqrt(3))/(sqrt(3)*sqrt(3)) = sqrt(72)/3 = sqrt(6^2*2)/3 = (sqrt(6^2)*sqrt(2))/3 = (6sqrt(2))/3 = 2sqrt(2)$

Alternatively, we can combine the numerator and denominator inside the square root:

$sqrt(24)/sqrt(3) = sqrt(24/3) = sqrt(8) = sqrt(2^2)*sqrt(2) = 2sqrt(2)$

How do you rationalize the denominator and simplify sqrt24/sqrt3sqrt24/sqrt3?