How do you rationalize the denominator and simplify $sqrt22/sqrt33$ ?

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Answer 1 · 2016-03-26T06:19:15

$sqrt22/sqrt33=sqrt6/3$

From the given $sqrt22/sqrt33=sqrt22/sqrt33*sqrt33/sqrt33$
$=sqrt(22*33)/(sqrt33)^2=sqrt(2*11*3*11)/33=sqrt(6*11^2)/33=(11sqrt6)/33=sqrt6/3$

God bless...I hope the explanation is useful.

How do you rationalize the denominator and simplify sqrt22/sqrt33sqrt22/sqrt33?