How do you rationalize the denominator and simplify $\frac{\sqrt{2} + \sqrt{3}}{2 \sqrt{2} - 3 \sqrt{3}}$ $(sqrt2+sqrt3)/(2sqrt2-3sqrt3)$ ?

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How do you rationalize the denominator and simplify $\frac{\sqrt{2} + \sqrt{3}}{2 \sqrt{2} - 3 \sqrt{3}}$ $(sqrt2+sqrt3)/(2sqrt2-3sqrt3)$ ?

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Answer 1 · 2016-03-14T17:53:27

$- \frac{13 + 5 \sqrt{6}}{19}$ $- ( 13 + 5sqrt6 )/19$

Explanation:

Multiply both numerator and denominator by the conjugate $(2 \sqrt{2} + 3 \sqrt{3})$ $( 2sqrt2 + 3sqrt3 )$ of the denominator and use $(a - b) (a + b) = (a^{2} - b^{2})$ $( a - b )( a + b ) = (a^2 - b^2 )$
Denominator is rationalized to $(- 19)$ $(-19)$ .

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How do you rationalize the denominator and simplify $\frac{\sqrt{2} + \sqrt{3}}{2 \sqrt{2} - 3 \sqrt{3}}$ $(sqrt2+sqrt3)/(2sqrt2-3sqrt3)$ ?

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How do you rationalize the denominator and simplify √2+√32√2−3√3(sqrt2+sqrt3)/(2sqrt2-3sqrt3)?

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How do you rationalize the denominator and simplify $\frac{\sqrt{2} + \sqrt{3}}{2 \sqrt{2} - 3 \sqrt{3}}$ $(sqrt2+sqrt3)/(2sqrt2-3sqrt3)$ ?