How do you rationalize the denominator and simplify #sqrt18/sqrt3#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Sam May 14, 2016 #18=3*3*2 = 3^2*2# #sqrt(18)/sqrt(3)# #sqrt(3^2*2)/sqrt(3)# #(sqrt(3^2)*sqrt(2))/sqrt(3)# #(3*sqrt(2))/sqrt(3)# #(3*sqrt(2))/sqrt(3)*(sqrt(3))/(sqrt(3))# #(3*sqrt(2)*sqrt(3))/3# #(cancel(3)*sqrt(2)*sqrt(3))/cancel(3)# #sqrt(2*3)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1137 views around the world You can reuse this answer Creative Commons License