How do you rationalize the denominator and simplify (sqrt 6 - 3 ) / 4√6−34?
1 Answer
May 4, 2016
denominator is already rationalised
Explanation:
The set of rational numbers Q are expressed in the form
a/bab where a,b
inZ, b≠0∈Z,b≠0 now 4 is in this form ie.
4/1rArr " in rational form "41⇒ in rational form Normally require to rationalise the denominator when the radical is on the denominator, which is not the case here.
For example , if
sqrt6 -3 " was on the denominator "√6−3 was on the denominator Then to rationalise , we multiply by it's Conjugate
• " conjugate of "sqrta ± b " is " sqrta ∓ b∙ conjugate of √a±b is √a∓b and multiplying by the conjugate produces a rational number
rArr(sqrt6-3)(sqrt6+3)=(sqrt6)^2+3sqrt6-3sqrt6-9⇒(√6−3)(√6+3)=(√6)2+3√6−3√6−9
=6-9=-3" a rational value "=6−9=−3 a rational value
