How do you rationalize the denominator and simplify sqrt(245/3)? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Shwetank Mauria Jul 11, 2016 sqrt(245/3)=(7sqrt15)/3 Explanation: sqrt(245/3)=sqrt245/sqrt3 As we have sqrt3 in denominator, we need to multiply it by sqrt3, that will make the denominator sqrt9=3 and thus rationalise the denominator. But as we multiply denominator by sqrt3. we should also multiply numerator by sqrt3. Hence, sqrt(245/3)=sqrt245/sqrt3 = (sqrt245×sqrt3)/(sqrt3×sqrt3 = sqrt735/3 = sqrt(3×5×ul(7×7))/3 = (7sqrt15)/3 Answer link Related questions How do you simplify \frac{2}{\sqrt{3}}? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify 7/(""^3sqrt(5)? How do you multiply (sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))? How do you rationalize the denominator for \frac{2x}{\sqrt{5}x}? Do you always have to rationalize the denominator? How do you simplify sqrt(5)sqrt(15)? How do you simplify (7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))? See all questions in Multiplication and Division of Radicals Impact of this question 1289 views around the world You can reuse this answer Creative Commons License