How do you rationalize the denominator and simplify $sqrt(12x^3)/sqrt(7y^5)$ ?

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Answer 1 · 2016-03-23T12:07:02

$sqrt(12x^3)/sqrt(7y^5)= 2sqrt(21x^3y^5)/(7y^5)$

Or more simplified:

$sqrt(12x^3)/sqrt(7y^5)=(2x)/(7y^3)*sqrt(21xy)$

To rationalize your expression, the idea is to multiply it by a therm that doesn't change it but cancels the $sqrt()$ at the denominator.

Therefore:

$sqrt(12x^3)/sqrt(7y^5)=sqrt(12x^3)/sqrt(7y^5)*sqrt(7y^5)/sqrt(7y^5)=$

$=(sqrt(12x^3)*sqrt(7y^5))/(sqrt(7y^5*7y^5))=$

$=sqrt(12x^3*7y^5)/(sqrt((7y^5)^2))=sqrt(3*2^2*7x^3y^5)/(7y^5)=2sqrt(21x^3y^5)/(7y^5)$

Now you can more simplify the results:

$2sqrt(21x^3y^5)/(7y^5)=2sqrt(21x^2*x*y^4*y)/y^5=2xcancel(y^2)sqrt(21xy)/(7y^(cancel(5)^3))=$
$=(2x)/(7y^3)*sqrt(21xy)$

How do you rationalize the denominator and simplify sqrt(12x^3)/sqrt(7y^5)sqrt(12x^3)/sqrt(7y^5)?