How do you rationalize the denominator and simplify $\frac{{cos}^{2} x}{1 - sin x}$ $(cos^2 x) /( 1- sin x)$ ?

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How do you rationalize the denominator and simplify $\frac{{cos}^{2} x}{1 - sin x}$ $(cos^2 x) /( 1- sin x)$ ?

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Answer 1 · 2016-04-02T14:15:21

$\frac{{cos}^{2} x}{1 - sin x} \times \frac{1 + sin x}{1 + sin x} = (\frac{{cos}^{2} x}{1 - {sin}^{2} x} \times (1 + sin x))$ $(cos^2x)/(1-sinx)xx(1+sinx)/(1+sinx)=((cos^2x)/(1-sin^2x)xx(1+sinx))$
$=(cancelcos^2x)/(cancelcos^2x)(1+sinx)=1+sinx$

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How do you rationalize the denominator and simplify $\frac{{cos}^{2} x}{1 - sin x}$ $(cos^2 x) /( 1- sin x)$ ?

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How do you rationalize the denominator and simplify $\frac{{cos}^{2} x}{1 - sin x}$ $(cos^2 x) /( 1- sin x)$ ?