How do you rationalize the denominator and simplify $(8-6sqrt5)/sqrt12$ ?

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Answer 1 · 2017-03-01T17:27:44

$[8-6 sqrt5]/sqrt12 = [2(4-3sqrt5)]/sqrt(4xx3)$

$rArr [2(4-3sqrt5)]/[2sqrt3]$

$rArr [4-3sqrt5]/[sqrt3]$ multiply D & N BY $sqrt3$

$rArr [sqrt3(4-3sqrt5)]/[sqrt3 sqrt3]$

$rArr[sqrt3(4-3sqrt5)]/3$

How do you rationalize the denominator and simplify (8-6sqrt5)/sqrt12(8-6sqrt5)/sqrt12?