How do you rationalize the denominator and simplify #(7sqrt8)/(4sqrt56)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 2 Answers mizoo Apr 11, 2018 # sqrt7/4# Explanation: #(7sqrt8)/(4sqrt56) xx sqrt56/sqrt56# #= (7sqrt8xx sqrt56)/(4xx56)# #= (7sqrt(8xx 8xx7))/(4xx56)# #= (7 xx 8 sqrt7)/(4xx56)# # = sqrt7/4# Answer link Barney V. Apr 11, 2018 #sqrt7/4# Explanation: #(7 sqrt 8)/(4 sqrt 56)# #:.=(7 sqrt(2*2*2))/(4 sqrt(14*4))# #sqrt2*sqrt2=2# #:.=(14 sqrt2)/(8 sqrt14)# #:.=(14 sqrt2)/(8 sqrt14)xx(8 sqrt14)/(8 sqrt14)# #:.=(cancel 112^1 sqrt 28)/cancel 896^8# #:.=(sqrt 28)/8# #:.=sqrt(2*2*7)/8# #:.=(2 sqrt 7)/8# #:.=sqrt 7/4# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1379 views around the world You can reuse this answer Creative Commons License