How do you rationalize the denominator and simplify $\frac{7}{\sqrt{x} + \sqrt{y}}$ $7/(sqrtx+sqrty)$ ?

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How do you rationalize the denominator and simplify $\frac{7}{\sqrt{x} + \sqrt{y}}$ $7/(sqrtx+sqrty)$ ?

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Answer 1 · 2016-03-16T02:22:53

$7 \frac{\sqrt{x} - \sqrt{y}}{x - y}$ $7(sqrtx-sqrty)/(x-y)$

Explanation:

Multiply both numerator and denominator by the conjugate of the denominator $\sqrt{x} - \sqrt{y}$ $sqrtx-sqrty$ and use
$(a^{2} - b^{2}) = (a - b) (a + b)$ $(a^2-b^2)=(a-b)(a+b)$

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How do you rationalize the denominator and simplify $\frac{7}{\sqrt{x} + \sqrt{y}}$ $7/(sqrtx+sqrty)$ ?

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How do you rationalize the denominator and simplify 7/(sqrtx+sqrty)7√x+√y7/(sqrtx+sqrty)?

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How do you rationalize the denominator and simplify $\frac{7}{\sqrt{x} + \sqrt{y}}$ $7/(sqrtx+sqrty)$ ?