How do you rationalize the denominator and simplify #(6sqrt5)/(sqrt15 +2)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Mark D. Apr 17, 2018 #(30sqrt3-12sqrt5)/11# Explanation: #(6sqrt5)/(sqrt(15)+2)##xx# #(sqrt(15)-2)/(sqrt(15)-2)# #=># #(6sqrt75-12sqrt5)/(15-2sqrt15+2sqrt15-4)# #=># #(30sqrt3-12sqrt5)/11# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1250 views around the world You can reuse this answer Creative Commons License