How do you rationalize the denominator and simplify $6/(sqrt4+sqrt5)$ ?

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Answer 1 · 2016-03-24T03:32:15

$6(sqrt5+-2)$

Multiply numerator and denominator by the conjugate $sqrt5-sqrt4$ of the denominator and use $(a-b)(a+b)=(a^2-b^2)$ . Hence,

$6/(sqrt5+2)=(6(sqrt5-2))/ ((sqrt5-2)(sqrt5+2))$ or

$(6(sqrt5-2))/(5-4)$ or

$6(sqrt5-2)$

How do you rationalize the denominator and simplify 6/(sqrt4+sqrt5)6/(sqrt4+sqrt5)?