How do you rationalize the denominator and simplify #6/(3-sqrt3)#?

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How do you rationalize the denominator and simplify #6/(3-sqrt3)#?

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Answer 1 · 2016-07-21T20:29:16

#3+sqrt3#

Explanation:

#6/(3-sqrt3)#
Multiplying both numerator and denominator by #3+sqrt3#
we get
#6(3+sqrt3)/((3-sqrt3)(3+sqrt3)#
OR
#6(3+sqrt3)/(3^2-(sqrt3)^2)#
OR
#6(3+sqrt3)/(9-3)#
OR
#6(3+sqrt3)/6#
OR
#3+sqrt3#

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How do you rationalize the denominator and simplify #6/(3-sqrt3)#?

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