How do you rationalize the denominator and simplify #5/(sqrt6+sqrt15)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer F. Javier B. Apr 2, 2018 See below Explanation: #5/(sqrt6+sqrt15)=(5(sqrt6-sqrt15))/((sqrt6+sqrt15)(sqrt6-sqrt15))# #=(5sqrt6-5sqrt15)/(6-15)=(5sqrt6-5sqrt15)/-9=-5/9(sqrt6-sqrt15)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1016 views around the world You can reuse this answer Creative Commons License