How do you rationalize the denominator and simplify #5/(sqrt6-2)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer GiĆ³ · Jumbotron Aug 5, 2018 I tried this: Explanation: Let us multiply and divide by #sqrt(6)+2#: #5/(sqrt(6)-2)*color(red)((sqrt(6)+2)/(sqrt(6)+2))# #=(5sqrt(6) + 10)/(6-4)# #=(5 sqrt(6)+10)/2# #=5/2sqrt(6)+5# #=5(sqrt(6)/2+1)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1468 views around the world You can reuse this answer Creative Commons License