How do you rationalize the denominator and simplify #(5 sqrt 6) / sqrt 10#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Nityananda Jan 14, 2017 #sqrt 15# Explanation: given, #[5 sqrt 6]/sqrt 10 # #rArr [5 sqrt2 sqrt3]/[sqrt 2 sqrt 5 # #rArr [5sqrt 3] /sqrt5# #rArr [sqrt 5 sqrt 5 sqrt 3]/sqrt 5# #rArrsqrt 5 sqrt 3# #rArrsqrt15# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 954 views around the world You can reuse this answer Creative Commons License