How do you rationalize the denominator and simplify 4sqrt(7/(2z^2))?

1 Answer

color(blue)(4sqrt(7/(2z^2))=(2sqrt(14))/z)

color(red)(root4(7/(2z^2))=root4(56z^2)/(2z))

Explanation:

If the given is to simplify 4sqrt(7/(2z^2)

The solution:

4sqrt(7/(2z^2))=4sqrt(7/(2z^2)*2/2)=4sqrt(14/(4z^2))=(4sqrt(14))/(2z)=(2sqrt(14))/z

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If the given is to simplify root4(7/(2z^2))

The solution:

root4(7/(2z^2))=root4(7/(2z^2)*((8z^2)/(8z^2)))=root4((56z^2)/(16z^4))=root4(56z^2)/(2z)

God bless....I hope the explanation is useful.