How do you rationalize the denominator and simplify #4sqrt(7/(2z^2))#?

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Answer 1 · 2016-07-31T05:30:33

#color(blue)(4sqrt(7/(2z^2))=(2sqrt(14))/z)#

#color(red)(root4(7/(2z^2))=root4(56z^2)/(2z))#

If the given is to simplify #4sqrt(7/(2z^2)#

The solution:

#4sqrt(7/(2z^2))=4sqrt(7/(2z^2)*2/2)=4sqrt(14/(4z^2))=(4sqrt(14))/(2z)=(2sqrt(14))/z#

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If the given is to simplify #root4(7/(2z^2))#

The solution:

#root4(7/(2z^2))=root4(7/(2z^2)*((8z^2)/(8z^2)))=root4((56z^2)/(16z^4))=root4(56z^2)/(2z)#

God bless....I hope the explanation is useful.