How do you rationalize the denominator and simplify #(3sqrt2)/sqrt6#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Don't Memorise Mar 20, 2016 # = sqrt12 / 2# Explanation: #(3sqrt2) / sqrt6# # = (3sqrt2 * color(blue)(sqrt6)) / (sqrt6 * color(blue)(sqrt6)# # = (3 * sqrt2 * color(blue)(sqrt6)) / 6# # = (3 sqrt12 ) / 6# # = (cancel3 sqrt12 ) / cancel6# # = sqrt12 / 2# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1028 views around the world You can reuse this answer Creative Commons License