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How do you rationalize the denominator and simplify #(3sqrt2)/sqrt6#?

1 Answer

Mar 20, 2016

# = sqrt12 / 2#

Explanation:

#(3sqrt2) / sqrt6#

# = (3sqrt2 * color(blue)(sqrt6)) / (sqrt6 * color(blue)(sqrt6)#

# = (3 * sqrt2 * color(blue)(sqrt6)) / 6#

# = (3 sqrt12 ) / 6#

# = (cancel3 sqrt12 ) / cancel6#

# = sqrt12 / 2#

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