How do you rationalize the denominator and simplify $\frac{3}{\sqrt{3} - 1}$ $3/(sqrt3-1)$ ?

Question

How do you rationalize the denominator and simplify $\frac{3}{\sqrt{3} - 1}$ $3/(sqrt3-1)$ ?

1 Answer

Impact of this question

956 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-01T13:09:59

$= 3 \frac{\sqrt{3} + 1}{2}$ $=3(sqrt3+1)/2$

Explanation:

Multiplying numerator and denominator of $\frac{3}{\sqrt{3} - 1}$ $3/(sqrt3-1)$ by $\sqrt{3} + 1$ $sqrt3+1$
we get
$3 \frac{\sqrt{3} + 1}{(\sqrt{3} - 1) (\sqrt{3} + 1)}$ $3(sqrt3+1)/((sqrt3-1)(sqrt3+1)$
$= 3 \frac{\sqrt{3} + 1}{3 - 1}$ $=3(sqrt3+1)/(3-1)$
$= 3 \frac{\sqrt{3} + 1}{2}$ $=3(sqrt3+1)/2$

Science

Math

Humanities

... and beyond

How do you rationalize the denominator and simplify $\frac{3}{\sqrt{3} - 1}$ $3/(sqrt3-1)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you rationalize the denominator and simplify 3√3−13/(sqrt3-1)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you rationalize the denominator and simplify $\frac{3}{\sqrt{3} - 1}$ $3/(sqrt3-1)$ ?