How do you rationalize the denominator and simplify #(3 sqrt 5 + 2) / (3 sqrt 5 + 5)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Binayaka C. Mar 13, 2016 #1/20(35-9sqrt5)# Explanation: multiplying by #3sqrt5-5# on both numerator and denominator we get #( (3sqrt5+2)*(3sqrt5-5))/(45-25)#=#((45-10-sqrt5(15-6))/20)# = #1/20(35-9sqrt5)#[answer] Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1011 views around the world You can reuse this answer Creative Commons License