How do you rationalize the denominator and simplify #3/(2+sqrt12)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer P dilip_k Apr 23, 2016 #3/(sqrt12+2)=3/(sqrt12+2)xx(sqrt12-2)/(sqrt12-2)# #=(3sqrt(2^2xx3)-6)/(12-2)=(6sqrt3-6)/10=6/10xx(sqrt3-1)# #=3/5xx(sqrt3-1)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 864 views around the world You can reuse this answer Creative Commons License