How do you rationalize the denominator and simplify $2/(sqrt6-sqrt5)$ ?

Question

1189 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-12T14:26:34

$2 (sqrt6 + sqrt5 )$

Multiply both numerator by the conjugate $sqrt6 + sqrt5$ of the denominator and use
$( a-b)(a + b)=( a^2-b^2)$

How do you rationalize the denominator and simplify 2/(sqrt6-sqrt5)2/(sqrt6-sqrt5)?