How do you rationalize the denominator and simplify $\frac{2 + \sqrt{3}}{\sqrt{3}}$ $(2+sqrt3)/sqrt3$ ?

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Answer 1 · 2018-03-13T12:15:22

See a solution process below:

Multiply by $\frac{\sqrt{3}}{\sqrt{3}}$ $sqrt(3)/sqrt(3)$ giving:

$\frac{\sqrt{3}}{\sqrt{3}} \times \frac{2 + \sqrt{3}}{\sqrt{3}} \Rightarrow$ $sqrt(3)/sqrt(3) xx (2 + sqrt(3))/sqrt(3) =>$

$\frac{\sqrt{3} (2 + \sqrt{3})}{\sqrt{3} \times \sqrt{3}} \Rightarrow$ $(sqrt(3)(2 + sqrt(3)))/(sqrt(3) xx sqrt(3)) =>$

$\frac{2 \sqrt{3} + \sqrt{3} \sqrt{3}}{3} \Rightarrow$ $(2sqrt(3) + sqrt(3)sqrt(3))/3 =>$

$\frac{2 \sqrt{3} + 3}{3}$ $(2sqrt(3) + 3)/3$

Or

$\frac{2 \sqrt{3}}{3} + \frac{3}{3} \Rightarrow$ $(2sqrt(3))/3 + 3/3 =>$

$\frac{2}{3} \sqrt{3} + 1$ $2/3sqrt(3) + 1$

How do you rationalize the denominator and simplify 2+√3√3(2+sqrt3)/sqrt3?