How do you rationalize the denominator and simplify $2/(sqrt[3] + sqrt[2])$ ?

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Answer 1 · 2016-03-16T16:30:31

Multiply the denominator and numerator with $sqrt3-sqrt2$

hence

$2*(sqrt3-sqrt2)/[(sqrt[3] + sqrt[2])*(sqrt3-sqrt2)]= 2*(sqrt3-sqrt2)/[sqrt3^2-sqrt2^2]= 2*(sqrt3-sqrt2)$

How do you rationalize the denominator and simplify 2/(sqrt[3] + sqrt[2])2/(sqrt[3] + sqrt[2])?