How do you rationalize the denominator and simplify $\frac{2}{3 - \sqrt{2}}$ $2/(3-sqrt2)$ ?

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Answer 1 · 2018-04-17T01:52:42

$\frac{2}{3 - \sqrt{2}} = \frac{2 (3 + \sqrt{2})}{7}$ $2/(3-sqrt2)=color(blue)((2(3+sqrt2))/7$

Simplify:

$\frac{2}{3 - \sqrt{2}}$ $2/(3-sqrt2)$

Rationalize the denominator by multiplying the numerator and denominator by $(3 + \sqrt{2})$ $(3+sqrt2)$ .

$\frac{2 (3 + \sqrt{2})}{(3 - \sqrt{2}) (3 + \sqrt{2})}$ $(2(3+sqrt2))/((3-sqrt2)(3+sqrt2))$

$\frac{2 (3 + \sqrt{2})}{9 - 2}$ $(2(3+sqrt2))/(9-2)$

$\frac{2 (3 + \sqrt{2})}{7}$ $(2(3+sqrt2))/7$

How do you rationalize the denominator and simplify 23−√22/(3-sqrt2)?