How do you rationalize the denominator and simplify #(18sqrt24)/(-3sqrt8)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Lucy Apr 14, 2018 #-6sqrt3# Explanation: #(18sqrt24)/(-3sqrt8)# #(18sqrt(6times4))/(-3sqrt(4times2))# #(36sqrt6)/(-6sqrt2)# #(-6sqrt6)/sqrt2timessqrt2/sqrt2# #(-6sqrt12)/2# #(-6sqrt(3times4))/2# #(-12sqrt3)/2# #-6sqrt3# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 893 views around the world You can reuse this answer Creative Commons License