How do you rationalize the denominator and simplify #12/root3(9)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Binayaka C. May 16, 2018 # 12/ root(3)9 = 4 root(3)3 # Explanation: # 12/ root(3)9# Multiplying by #9^(2/3)# on both numerator and denominator we get # (12*9^(2/3))/( root(3)9*9^(2/3))# #= (12*9^(2/3))/( 9^(1/3+2/3))=(12*root(3)81)/9# #(12*3*root(3)3)/9 = 4 root(3)3 # [Ans] Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1792 views around the world You can reuse this answer Creative Commons License