How do you rationalize the denominator $2/(sqrt[3] +sqrt[2])$ ?

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How do you rationalize the denominator $2/(sqrt[3] +sqrt[2])$ ?

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Answer 1 · 2015-04-12T19:41:13

You can multiply and divide by $sqrt(3)-sqrt(2)$ to get:
$2/(sqrt(3)+sqrt(2))(sqrt(3)-sqrt(2))/(sqrt(3)-sqrt(2))=$
$=(2*(sqrt(3)-sqrt(2)))/(3-2)=2*(sqrt(3)-sqrt(2))$

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How do you rationalize the denominator $2/(sqrt[3] +sqrt[2])$ ?

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