How do you rationalize sqrt22/sqrt33?

1 Answer
Gió
Mar 30, 2015

Write it as:
sqrt(22)/sqrt(33)=sqrt(22/33)= divide both by 11 =sqrt(2/3)
Now:
sqrt(2/3)=sqrt(2)/sqrt(3)=sqrt(2)/sqrt(3)*sqrt(3)/sqrt(3)=sqrt(6)/3

Or:
sqrt(22)/sqrt(33)*sqrt(33)/sqrt(33)=sqrt(22*33)/33=sqrt((2*11)(3*11))/33=sqrt(6*11^2)/33=11/33sqrt(6)=sqrt(6)/3

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