How do you rationalize #sqrt(5/8)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer GiĆ³ May 17, 2015 Write it as: #sqrt(5)/sqrt(8)# then multiply and divide by #sqrt(8)# to get: #sqrt(5)/sqrt(8)*sqrt(8)/sqrt(8)=(sqrt(5)sqrt(8))/8=# #=(sqrt(5)sqrt(4*2))/8=2(sqrt(5)sqrt(2))/8=(sqrt(5)sqrt(2))/4=sqrt(10)/4# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 2305 views around the world You can reuse this answer Creative Commons License