How do you rationalize denominator $(8)/ (sqrt5+sqrt2)$ ?

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Answer 1 · 2015-04-01T13:56:23

$8/3$ ( $sqrt5$ - $sqrt2$ )

Multiply the numerator and the denominator by the conjugate of $sqrt5$ + $sqrt2$ , which would be $sqrt5$ - $sqrt2$

On simplification we would have $8/3$ ( $sqrt5$ - $sqrt2$ )

[ ( $sqrt5$ + $sqrt2$ )( $sqrt5$ - $sqrt2$ ) = (5-2)=3]

How do you rationalize denominator (8)/ (sqrt5+sqrt2)(8)/ (sqrt5+sqrt2)?