How do you rationalize and simplify #5 / ( sqrt 14 - 2 )#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Massimiliano Mar 30, 2015 You have to multiply numerator and denominator by: #sqrt14+2#, so: #5/(sqrt14-2)*(sqrt14+2)/(sqrt14+2)=(5(sqrt14+2))/(14-4)=# #=(5(sqrt14+2))/10=(sqrt14+2)/2#. Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 3787 views around the world You can reuse this answer Creative Commons License