How do you rationalize $7/(sqrt3-sqrt2)$ ?

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How do you rationalize $7/(sqrt3-sqrt2)$ ?

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Answer 1 · 2015-05-08T16:37:53

7 $(sqrt3+sqrt2)$

Multiply the numerator and the denominator by $sqrt3+sqrt2$ , that would make the denominator $(sqrt3-sqrt2)(sqrt3+sqrt2)$ =3-2= 1. The result would be $7(sqrt3+sqrt2)$ . That is what was required.

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How do you rationalize $7/(sqrt3-sqrt2)$ ?

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How do you rationalize 7/(sqrt3-sqrt2)7/(sqrt3-sqrt2)?

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How do you rationalize $7/(sqrt3-sqrt2)$ ?