How do you rationalize $\frac{4}{6 - \sqrt{7}}$ $4/(6-sqrt7)$ ?

Question

1817 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-12T02:51:17

Multiply both numerator and denominator by $(6 + s q r 7)$ $(6 + sqr7)$

$\frac{4 (6 + s q r 7)}{36 - 7}$ $[4(6 + sqr7)]/(36 - 7)$ = $\frac{4 (6 + s q r 7)}{29}$ $[4(6 + sqr7)]/29$

How do you rationalize 46−√74/(6-sqrt7)?